2^{1000} = 10^{(log 2)1000}

Now 10^{1}, 10^{2}, and 10^{3} has 2, 3, and 4 digits respectively.

So 2^{1000} should have approximately (log 2)1000 + 1 digits.

skip to main |
skip to sidebar
## Thursday, October 2, 2008

###
How many digits does 2 "raise to" 1000 have?

Balagopal's Personal Blog.

We have to find decimal (base 10) digits. So convert to base 10.

2^{1000} = 10^{(log 2)1000}

Now 10^{1}, 10^{2}, and 10^{3} has 2, 3, and 4 digits respectively.

So 2^{1000} should have approximately (log 2)1000 + 1 digits.

Subscribe to:
Post Comments (Atom)

## No comments:

Post a Comment