Find the smallest number that when divided by n yields the remainder (n-1) for 2 <= n <= 10 (ie. dividing n by 10 yields 9, by 9 yields 8...).
Believe it or not, this was one of the questions asked for a 3rd standard annual exam (state syllabus).
Showing posts with label 3rd standard problem. Show all posts
Showing posts with label 3rd standard problem. Show all posts
Saturday, August 30, 2008
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